What is the vertices y=-2x^2 ?

The vertices y=-2x^2 is Maximum (0,0)

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vertices y=-2x^2

vertices

y = - 2 x^{2}

Maximum (0, 0)

Solution steps

y = - 2 x^{2}

The parabola parameters are:

a = - 2, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 ( - 2 )}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 2

Maximum (0, 0)

x^{2} - 2 x - 18

3 x - 4 y = 6

f (x) = ln (8 t), t > 0

y = 7 - x^{3}