{
"query": {
"display": "inverse $$f\\left(x\\right)=2\\sqrt{x-5}$$",
"symbolab_question": "FUNCTION#inverse f(x)=2\\sqrt{x-5}"
},
"solution": {
"level": "PERFORMED",
"subject": "Functions & Graphing",
"topic": "Functions",
"subTopic": "inverse",
"default": "\\frac{x^{2}}{4}+5",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "Inverse of $$2\\sqrt{x-5}:{\\quad}\\frac{x^{2}}{4}+5$$",
"steps": [
{
"type": "definition",
"title": "Function Inverse definition",
"text": "A function g is the inverse of function f if for $$y=f\\left(x\\right),\\:\\:x=g\\left(y\\right)\\:$$"
},
{
"type": "step",
"result": "y=2\\sqrt{x-5}"
},
{
"type": "interim",
"title": "Replace $$x\\:$$with $$y$$",
"input": "y=2\\sqrt{x-5}",
"result": "x=2\\sqrt{y-5}",
"steps": [
{
"type": "step",
"primary": "Replace $$x\\:$$with $$y$$",
"secondary": [
"Replace $$y\\:$$with $$x$$"
],
"result": "x=2\\sqrt{y-5}"
}
],
"meta": {
"interimType": "Interchange Variables 2Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7vpqcDD/7yX5Tbd9fO9JFZWFgdof0mln5sAB+dS/7ijCD0yqNoTWLwGuqxO0C0cFVz5Lb2DzoR+2lK1ma7A4yFw7HH89RUTaeN3FUkEAdGm+LD3IXcw26W+fH/nWE+8Jg6uvWjigmDRR62v/uo5/c/6/iRbMPfLQeIqHWmDQDbe8="
}
},
{
"type": "interim",
"title": "Solve for $$y,\\:x=2\\sqrt{y-5}$$",
"input": "x=2\\sqrt{y-5}",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "2\\sqrt{y-5}=x"
},
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2\\sqrt{y-5}=x",
"result": "\\sqrt{y-5}=\\frac{x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2\\sqrt{y-5}}{2}=\\frac{x}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\sqrt{y-5}=\\frac{x}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "Square both sides:$${\\quad}y-5=\\frac{x^{2}}{4}$$",
"input": "\\sqrt{y-5}=\\frac{x}{2}",
"result": "y-5=\\frac{x^{2}}{4}",
"steps": [
{
"type": "step",
"result": "\\left(\\sqrt{y-5}\\right)^{2}=\\left(\\frac{x}{2}\\right)^{2}"
},
{
"type": "interim",
"title": "Expand $$\\left(\\sqrt{y-5}\\right)^{2}:{\\quad}y-5$$",
"input": "\\left(\\sqrt{y-5}\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\left(\\left(y-5\\right)^{\\frac{1}{2}}\\right)^{2}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(a^{b}\\right)^{c}=a^{bc}$$",
"result": "=\\left(y-5\\right)^{\\frac{1}{2}\\cdot\\:2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "interim",
"title": "$$\\frac{1}{2}\\cdot\\:2=1$$",
"input": "\\frac{1}{2}\\cdot\\:2",
"result": "=y-5",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2}{2}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l3vTdf410Ywhq1vZ0kzF8e30Fwl9QKPJxyO/TFRCb5Grju+5Z51e/ZZSD3gRHwjBE9/03SOiEv+BIHutWLr6nUfz18ijmoplMAomfJM9x8W1GdKgiNs+PolKvTuWzYk/"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Expand Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7vz0OwVmz7FbkxdUH+eNAiYGUkcvOaxZAUm5h45yL0emJ9HQfN3qOfAB4kBd9UOFDpA7clkQOa7zoZEIDggSG4WRLd2VwIqlBNByF6663syTD7/TDV+MdcR0GdN6+1FDtJnWywhQ4lVjK8aMqVNSmlYmpXFf3SOUx+H18qfp3MLg="
}
},
{
"type": "interim",
"title": "Expand $$\\left(\\frac{x}{2}\\right)^{2}:{\\quad}\\frac{x^{2}}{4}$$",
"input": "\\left(\\frac{x}{2}\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(\\frac{a}{b}\\right)^{c}=\\frac{a^{c}}{b^{c}}$$",
"result": "=\\frac{x^{2}}{2^{2}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "$$2^{2}=4$$",
"result": "=\\frac{x^{2}}{4}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Expand Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7PYIowdXt2t1vjFLpvo+g6Gez183nLWWeYpvlsOrOijfptRYmj6WUpgaKrNIresW2wNmnTNPfSXaFwWcdWyIh039H/SFX0n2Ge344m0fgESR0U1L0UOfZXYZXOhi7eOgpx3URRsP3IGXaYScsUlze+fotFMd5aa71+dAhX5ea6wE="
}
},
{
"type": "step",
"result": "y-5=\\frac{x^{2}}{4}"
}
],
"meta": {
"interimType": "Radicals Square Both Sides Title 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDaZCNCMlwFw9Zrpnfgo8QW/WOwxW0IR0wYYVPLXyXeRYXflcl9kRnnQk+MFsuik2kQ1Bwl6I+B+YRPfML31vW1la1ygC+3Kr62ZdG5LvfiraN6Hv6MoTMtvtU0IQwXdn/oQmkZLMOYzj88wQWB+gSMtS4WPVolS0Rr7K51IRWwnQ=="
}
},
{
"type": "interim",
"title": "Solve $$y-5=\\frac{x^{2}}{4}:{\\quad}y=\\frac{x^{2}}{4}+5$$",
"input": "y-5=\\frac{x^{2}}{4}",
"steps": [
{
"type": "interim",
"title": "Move $$5\\:$$to the right side",
"input": "y-5=\\frac{x^{2}}{4}",
"result": "y=\\frac{x^{2}}{4}+5",
"steps": [
{
"type": "step",
"primary": "Add $$5$$ to both sides",
"result": "y-5+5=\\frac{x^{2}}{4}+5"
},
{
"type": "step",
"primary": "Simplify",
"result": "y=\\frac{x^{2}}{4}+5"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "y=\\frac{x^{2}}{4}+5"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve For Title 2Eq"
}
},
{
"type": "step",
"result": "\\frac{x^{2}}{4}+5"
}
],
"meta": {
"solvingClass": "Function Inverse"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "2\\sqrt{x-5}"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
inverse
Solution
Solution steps
Replace with
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Frequently Asked Questions (FAQ)
What is the inverse of f(x)=2sqrt(x-5) ?
The inverse of f(x)=2sqrt(x-5) is (x^2)/4+5