What is the derivative of-4cos(t) ?

The derivative of-4cos(t) is 4sin(t)

What is the first derivative of-4cos(t) ?

The first derivative of-4cos(t) is 4sin(t)

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derivative of

- 4 cos (t)

4 sin (t)

Solution steps

\frac{d}{d t} (- 4 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= - 4 (- sin (t))

Simplify

= 4 sin (t)

n = 0 \sum \infty \frac{3 n}{4 n - 1}

y = arctan (ln (2) x^{5})

f (x) = 5 x^{5} + \frac{2}{x}

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{5})

y = x^{2} - x + 9

What is the derivative of-4cos(t) ?
The derivative of-4cos(t) is 4sin(t)
What is the first derivative of-4cos(t) ?
The first derivative of-4cos(t) is 4sin(t)