What is the derivative of f(t)=7-1/3 t ?

The derivative of f(t)=7-1/3 t is -1/3

What is the first derivative of f(t)=7-1/3 t ?

The first derivative of f(t)=7-1/3 t is -1/3

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derivative of

f (t) = 7 - \frac{1}{3} t

- \frac{1}{3}

Decimal

- 0.33333 \dots

Solution steps

\frac{d}{d t} (7 - \frac{1}{3} t)

Simplify

7 - \frac{1}{3} t : 7 - \frac{t}{3}

= \frac{d}{d t} (7 - \frac{t}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (7) - \frac{d}{d t} (\frac{t}{3})

\frac{d}{d t} (7) = 0

\frac{d}{d t} (\frac{t}{3}) = \frac{1}{3}

= 0 - \frac{1}{3}

Simplify

= - \frac{1}{3}

\int \frac{7 x ^{2} + 5 x + 7}{( x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (y^{3})

\int_{1}^{6} x^{- 4} d x

\frac{d}{d x} (arccos (\frac{x + 1}{3}))

y^{^{'}} = x + y, y (0) = 0

What is the derivative of f(t)=7-1/3 t ?
The derivative of f(t)=7-1/3 t is -1/3
What is the first derivative of f(t)=7-1/3 t ?
The first derivative of f(t)=7-1/3 t is -1/3