What is area f(x)= 2/(x^2+1),|x| ?

The answer to area f(x)= 2/(x^2+1),|x| is (2pi-2)/2

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area f(x)= 2/(x^2+1),|x|

area

f (x) = \frac{2}{x ^{2} + 1}, ∣ x ∣

\frac{2 π - 2}{2}

Decimal

2.14159 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{2}{x ^{2} + 1} - ∣ x ∣ d x

Solve

\int_{- 1}^{1} \frac{2}{x ^{2} + 1} - ∣ x ∣ d x : \frac{2 π - 2}{2}

The area is:

= \frac{2 π - 2}{2}

\int (x - 1)^{2} sin^{2} (x) d x

t an g e n t f (x) = \frac{9}{x ^{2}}, at x = 3

\frac{\partial}{\partial x} (e^{- 7 y} sin (7 x))

\frac{d}{d x} (\frac{4 x}{5 2} + 3)

l a pl a ce t r an s f or m 25 t^{2}

What is area f(x)= 2/(x^2+1),|x| ?
The answer to area f(x)= 2/(x^2+1),|x| is (2pi-2)/2