What is the derivative of 9^{4x} ?

The derivative of 9^{4x} is 8ln(3)*6561^x

What is the first derivative of 9^{4x} ?

The first derivative of 9^{4x} is 8ln(3)*6561^x

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\frac{d}{d x} (9^{4 x})

8 ln (3) \cdot 656 1^{x}

Solution steps

\frac{d}{d x} (9^{4 x})

Simplify

9^{4 x} : 656 1^{x}

= \frac{d}{d x} (656 1^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 656 1^{x} ln (6561)

Simplify

ln (6561) : 8 ln (3)

= 8 ln (3) \cdot 656 1^{x}

\frac{d}{d x} (cot^{8} (x))

\int \frac{x ^{2}}{( x ^{2} - 1 ) ^{2}} d x

in v erse l a pl a ce - \frac{1}{s ^{4}}

\frac{d}{d x} (sin (1 - \frac{1}{x}))

\int_{0}^{π} 16 sin^{4} (x) d x

What is the derivative of 9^{4x} ?
The derivative of 9^{4x} is 8ln(3)*6561^x
What is the first derivative of 9^{4x} ?
The first derivative of 9^{4x} is 8ln(3)*6561^x