What is the tangent of f(x)=x^{1/2},(25,5) ?

The tangent of f(x)=x^{1/2},(25,5) is y= 1/10 x+5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=x^{1/2},(25,5)

tangent

y = \frac{1}{10} x + \frac{5}{2}

Solution steps

Find the slope of

f (x) = x^{\frac{1}{2}} : \frac{df ( x )}{d x} = \frac{1}{2 x ^{\frac{1}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{10}

Find the line with slope m=

\frac{1}{10}

and passing through

(25, 5) : y = \frac{1}{10} x + \frac{5}{2}

y = \frac{1}{10} x + \frac{5}{2}

What is the tangent of f(x)=x^{1/2},(25,5) ?
The tangent of f(x)=x^{1/2},(25,5) is y= 1/10 x+5/2