What is the integral of 3x^2e^{9x^3} ?

The integral of 3x^2e^{9x^3} is 1/9 e^{9x^3}+C

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integral of 3x^2e^{9x^3}

\int 3 x^{2} e^{9 x^{3}} d x

\frac{1}{9} e^{9 x^{3}} + C

Solution steps

\int 3 x^{2} e^{9 x^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x^{2} e^{9 x^{3}} d x

Apply u-substitution

: \int \frac{e ^{u}}{27} d u

= 3 \cdot \int \frac{e ^{u}}{27} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{27} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 3 \cdot \frac{1}{27} e^{u}

Substitute back

u = 9 x^{3}

= 3 \cdot \frac{1}{27} e^{9 x^{3}}

Simplify

3 \cdot \frac{1}{27} e^{9 x^{3}} : \frac{1}{9} e^{9 x^{3}}

= \frac{1}{9} e^{9 x^{3}}

Add a constant to the solution

= \frac{1}{9} e^{9 x^{3}} + C

f (x) = \frac{x - 1}{x + 3}

\int_{0}^{\infty} e^{(- 2 x)} d x

4^{(x^{9})}

\frac{1}{( 2 + x ) ^{3}}

x \to - \infty lim (3^{- x})

What is the integral of 3x^2e^{9x^3} ?
The integral of 3x^2e^{9x^3} is 1/9 e^{9x^3}+C