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tangent y=arctan(-x),\at x=4

解答

切线

y = arctan (- x), at x = 4

解答

y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

求解步骤

找到切点:

(4, - arctan (4))

计算

y = arctan (- x)

的斜率:

\frac{d y}{d x} = - \frac{1}{x ^{2} + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{17}

找到斜率 m=

- \frac{1}{17}

且穿过

(4, - arctan (4))

的直线:

y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

作图

流行的例子

derivative y=x^4e^{2x}

d er i v a t i v e y = x^{4} e^{2 x}

limit as x approaches 0+of 4/x-4/(|x|)

x \to 0 + lim (\frac{4}{x} - \frac{4}{∣ x ∣})

斜率 (790,77880),(970,94440)

s l o p e (790, 77880), (970, 94440)

integral of 3/37 x^2

\int \frac{3}{37} x^{2} d x

derivative of 9/(4\sqrt[4]{x^3})

\frac{d}{d x} (\frac{9}{4 4 x ^{3}})