What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0 ?

The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1

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(x^2+1)((dy)/(dx))+3x(y-1)=0

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

\frac{\partial}{\partial x} (7 x ln (x y))

\frac{d}{d x} (1 3^{x})

\int_{2}^{4} \frac{1}{∣ x - 3 ∣ ^{\frac{1}{2}}} d x

f (x) = x^{2} + x, at x = - 4, - 1

\int - \frac{2}{y} d y

What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0 ?
The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1