What is the solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=4 ?

The solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=4 is y=-4e^{2t}+12e^{2t}t

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y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=4

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = - 4, y^{^{'}} (0) = 4

y = - 4 e^{2 t} + 12 e^{2 t} t

Solution steps

y^{''} (t) - 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = - 4 e^{2 t} + 12 e^{2 t} t

y = - 4 e^{2 t} + 12 e^{2 t} t

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What is the solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=4 ?
The solution for y^{''}-4y^'+4y=0,y(0)=-4,y^'(0)=4 is y=-4e^{2t}+12e^{2t}t