What is the derivative of ln(5e^{-4x}) ?

The derivative of ln(5e^{-4x}) is -4

What is the first derivative of ln(5e^{-4x}) ?

The first derivative of ln(5e^{-4x}) is -4

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\frac{d}{d x} (ln (5 e^{- 4 x}))

- 4

Solution steps

\frac{d}{d x} (ln (5 e^{- 4 x}))

Simplify

ln (5 e^{- 4 x}) : ln (5) - 4 x

= \frac{d}{d x} (ln (5) - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (5)) - \frac{d}{d x} (4 x)

\frac{d}{d x} (ln (5)) = 0

\frac{d}{d x} (4 x) = 4

= 0 - 4

Simplify

= - 4

\int \frac{x}{x ^{2} + 4 x + 3} d x

\int \frac{1}{4 - y} d y

x \to 8 + lim (\frac{x - 8}{∣ x - 8 ∣})

y = 3 x^{2} - 2 x, at x = - 1

\frac{d}{d x} (x^{2} (x - 2)^{4})

What is the derivative of ln(5e^{-4x}) ?
The derivative of ln(5e^{-4x}) is -4
What is the first derivative of ln(5e^{-4x}) ?
The first derivative of ln(5e^{-4x}) is -4