What is the solution for xy^'+3y=((e^x))/x ?

The solution for xy^'+3y=((e^x))/x is y=(e^x)/(x^2)-(e^x)/(x^3)+(c_{1})/(x^3)

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xy^'+3y=((e^x))/x

x y^{^{'}} + 3 y = \frac{( e ^{x} )}{x}

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

Solution steps

x y^{'} (x) + 3 y = \frac{( e ^{x} )}{x}

Solve linear ODE:

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

\frac{\partial}{\partial y} (5 x sin (y))

in v erse l a pl a ce 3 x^{2}

\int x^{- 3} d x

\frac{\partial}{\partial x} (e^{- (x^{7} + y^{7})})

\frac{d y}{d x} = e^{x + y} + x^{2} e^{y}

What is the solution for xy^'+3y=((e^x))/x ?
The solution for xy^'+3y=((e^x))/x is y=(e^x)/(x^2)-(e^x)/(x^3)+(c_{1})/(x^3)