derivative of (x^2-9x+20/((x+2)(x-2)))

Lösung

\frac{d}{d x} (\frac{x ^{2} - 9 x + 20}{( x + 2 ) ( x - 2 )})

\frac{9 x ^{2} - 48 x + 36}{( x + 2 ) ^{2} ( x - 2 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 9 x + 20}{( x + 2 ) ( x - 2 )})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 9 x + 20 ) ( x + 2 ) ( x - 2 ) - \frac{d}{d x} ( ( x + 2 ) ( x - 2 ) ) ( x ^{2} - 9 x + 20 )}{( ( x + 2 ) ( x - 2 ) ) ^{2}}

\frac{d}{d x} (x^{2} - 9 x + 20) = 2 x - 9

\frac{d}{d x} ((x + 2) (x - 2)) = 2 x

= \frac{( 2 x - 9 ) ( x + 2 ) ( x - 2 ) - 2 x ( x ^{2} - 9 x + 20 )}{( ( x + 2 ) ( x - 2 ) ) ^{2}}

Vereinfache

\frac{( 2 x - 9 ) ( x + 2 ) ( x - 2 ) - 2 x ( x ^{2} - 9 x + 20 )}{( ( x + 2 ) ( x - 2 ) ) ^{2}} : \frac{9 x ^{2} - 48 x + 36}{( x + 2 ) ^{2} ( x - 2 ) ^{2}}

= \frac{9 x ^{2} - 48 x + 36}{( x + 2 ) ^{2} ( x - 2 ) ^{2}}

\frac{d}{d x} ((lo g_{10} (x))^{s i n h (x)})

t an g e n t f (x) = x^{2} - 4, at a = 1

\int_{5}^{9} (9 - y + 2)^{2} d y

x \to 2 lim (\frac{1}{2} x + c)

\frac{d}{d x} (\frac{x + 2}{3 x - 4})