9(t+1)y^'-5y=20t

Lösung

9 (t + 1) y^{^{'}} - 5 y = 20 t

y = 5 t + 9 + c_{1} (t + 1)^{\frac{5}{9}}

Schritte zur Lösung

9 (t + 1) y^{'} (t) - 5 y = 20 t

Solve linear ODE:

y = 5 t + 9 + c_{1} (t + 1)^{\frac{5}{9}}

y = 5 t + 9 + c_{1} (t + 1)^{\frac{5}{9}}

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