What is the solution for y^'+y+1/x y=(e^{-x})/x ?

The solution for y^'+y+1/x y=(e^{-x})/x is y= 1/(e^x)+(c_{1})/(e^xx)

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y^'+y+1/x y=(e^{-x})/x

y^{^{'}} + y + \frac{1}{x} y = \frac{e ^{- x}}{x}

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{x} x}

Solution steps

y^{'} (x) + y + \frac{1}{x} y = \frac{e ^{- x}}{x}

Solve linear ODE:

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{x} x}

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{x} x}

f (x) = x^{\frac{9}{2}}

3 y^{^{''}} - 4 y^{^{'}} - 15 y = 0

\frac{2}{3} (x^{2} + 1)^{\frac{3}{2}}

\frac{\partial}{\partial x} (arcsin (5 x yz))

\int e^{3 x} x d x

What is the solution for y^'+y+1/x y=(e^{-x})/x ?
The solution for y^'+y+1/x y=(e^{-x})/x is y= 1/(e^x)+(c_{1})/(e^xx)