What is the derivative of (x^2+1^2) ?

The derivative of (x^2+1^2) is 4x(x^2+1)

What is the first derivative of (x^2+1^2) ?

The first derivative of (x^2+1^2) is 4x(x^2+1)

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\frac{d}{d x} ((x^{2} + 1)^{2})

4 x (x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{2})

Apply the chain rule:

2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

= 2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 2 (x^{2} + 1) \cdot 2 x

Simplify

= 4 x (x^{2} + 1)

n = 0 \sum \infty \frac{n ^{2}}{n !}

\frac{d}{d x} (sin (3 x) ln (sech (2 x)))

\frac{\partial}{\partial y} (ln (x^{2} + y^{2} + 2))

n = 1 \sum \infty \frac{x ^{n}}{1 ^{n}}

\int (1 + x)^{3} d x

What is the derivative of (x^2+1^2) ?
The derivative of (x^2+1^2) is 4x(x^2+1)
What is the first derivative of (x^2+1^2) ?
The first derivative of (x^2+1^2) is 4x(x^2+1)