en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=y(1-y),y(0)=12

Solution

y^{^{'}} = y (1 - y), y (0) = 12

Solution

y = - \frac{12 e ^{t}}{11 - 12 e ^{t}}

Solution steps

y^{'} (t) = y (1 - y)

Solve separable ODE:

y = - \frac{12 e ^{t}}{11 - 12 e ^{t}}

y = - \frac{12 e ^{t}}{11 - 12 e ^{t}}

Popular Examples

integral of 1/(x^2sqrt(3x-1))

\int \frac{1}{x ^{2} 3 x - 1} d x

integral of 2x(x^2+3)^4

\int 2 x (x^{2} + 3)^{4} d x

(\partial)/(\partial y)(ysin(xy))

\frac{\partial}{\partial y} (y sin (x y))

derivative of (ln(x)^5)

\frac{d}{d x} ((ln (x))^{5})

integral of 8xe^{8x}

\int 8 x e^{8 x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y(1-y),y(0)=12 ?
The solution for y^'=y(1-y),y(0)=12 is y=-(12e^t)/(11-12e^t)