d/(dt)((arccos(t))^2)

解答

\frac{d}{d t} ((arccos (t))^{2})

- \frac{2 arccos ( t )}{1 - t ^{2}}

求解步骤

\frac{d}{d t} ((arccos (t))^{2})

使用连锁律:

2 arccos (t) \frac{d}{d t} (arccos (t))

= 2 arccos (t) \frac{d}{d t} (arccos (t))

\frac{d}{d t} (arccos (t)) = - \frac{1}{1 - t ^{2}}

= 2 arccos (t) (- \frac{1}{1 - t ^{2}})

化简

2 arccos (t) (- \frac{1}{1 - t ^{2}}) : - \frac{2 arccos ( t )}{1 - t ^{2}}

= - \frac{2 arccos ( t )}{1 - t ^{2}}

\int 2 cos^{3} (4 x) d x

\frac{\partial}{\partial v} (2 uv)

d er i v a t i v e \frac{f ( x )}{x ^{7}}

x \to 0 lim ((5 + x)^{x})

(2 x e^{x} - y^{2}) d x + 2 y d y = 0