What is the sum from n=0 to infinity of (-1)^n(n+1) ?

The sum from n=0 to infinity of (-1)^n(n+1) is diverges

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sum from n=0 to infinity of (-1)^n(n+1)

n = 0 \sum \infty (- 1)^{n} (n + 1)

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} (n + 1)

Apply Series Divergence Test:

diverges

= diverges

\int x e^{(- x)} d x

f (x) = e^{l n (x)} - e^{5 l n (x^{2})}

f (x) = tan (x) cot (x)

\frac{d}{d x} (\frac{3}{( x - 4 ) ^{2}})

\frac{d}{d x} (arcsin (\frac{1}{2} x))

What is the sum from n=0 to infinity of (-1)^n(n+1) ?
The sum from n=0 to infinity of (-1)^n(n+1) is diverges