What is the solution for xydy-(x^2+y^2)dx=0 ?

The solution for xydy-(x^2+y^2)dx=0 is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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xydy-(x^2+y^2)dx=0

x y d y - (x^{2} + y^{2}) d x = 0

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

x y d y - (x^{2} + y^{2}) d x = 0

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

n = 1 \sum \infty \frac{1}{( 0.8 ) ^{n}}

\int_{0}^{2} x^{2} 4 - x^{2} d x

f (x) = \frac{- 8 x}{x ^{2} + 1}

3 t + 2

x \to - 2 lim (x^{2} + 2 x - 3)

What is the solution for xydy-(x^2+y^2)dx=0 ?
The solution for xydy-(x^2+y^2)dx=0 is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}