What is the derivative of (sin(3x)/(cos(3x))) ?

The derivative of (sin(3x)/(cos(3x))) is sec^2(3x)*3

What is the first derivative of (sin(3x)/(cos(3x))) ?

The first derivative of (sin(3x)/(cos(3x))) is sec^2(3x)*3

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\frac{d}{d x} (\frac{sin ( 3 x )}{cos ( 3 x )})

sec^{2} (3 x) \cdot 3

Solution steps

\frac{d}{d x} (\frac{sin ( 3 x )}{cos ( 3 x )})

Simplify

\frac{sin ( 3 x )}{cos ( 3 x )} : tan (3 x)

= \frac{d}{d x} (tan (3 x))

Apply the chain rule:

sec^{2} (3 x) \frac{d}{d x} (3 x)

= sec^{2} (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= sec^{2} (3 x) \cdot 3

x \to 2 lim (e^{2 x - x^{2}})

\int y e^{z} d z

\int \frac{x ^{4} + 1}{x ^{3}} d x

x \to 3 lim (\frac{2}{( x - 3 ) ^{3}})

What is the derivative of (sin(3x)/(cos(3x))) ?
The derivative of (sin(3x)/(cos(3x))) is sec^2(3x)*3
What is the first derivative of (sin(3x)/(cos(3x))) ?
The first derivative of (sin(3x)/(cos(3x))) is sec^2(3x)*3