What is the derivative of x^{3/2}+4 ?

The derivative of x^{3/2}+4 is (3x^{1/2})/2

What is the first derivative of x^{3/2}+4 ?

The first derivative of x^{3/2}+4 is (3x^{1/2})/2

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\frac{d}{d x} (x^{\frac{3}{2}} + 4)

\frac{3 x ^{\frac{1}{2}}}{2}

Solution steps

\frac{d}{d x} (x^{\frac{3}{2}} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{3}{2}}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{\frac{3}{2}}) = \frac{3 x ^{\frac{1}{2}}}{2}

\frac{d}{d x} (4) = 0

= \frac{3 x ^{\frac{1}{2}}}{2} + 0

Simplify

= \frac{3 x ^{\frac{1}{2}}}{2}

y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = 0

\frac{d}{d x} ((1 + e^{- x})^{x})

\int 3 x^{3} e^{3 x} d x

t an g e n t f (x) = x^{2} + x, 4, at x = 2

\int \frac{18}{1 - cos ( 6 x )} d x

What is the derivative of x^{3/2}+4 ?
The derivative of x^{3/2}+4 is (3x^{1/2})/2
What is the first derivative of x^{3/2}+4 ?
The first derivative of x^{3/2}+4 is (3x^{1/2})/2