What is the integral of (x^2)/(16) ?

The integral of (x^2)/(16) is (x^3)/(48)+C

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integral of (x^2)/(16)

\int \frac{x ^{2}}{16} d x

\frac{x ^{3}}{48} + C

Solution steps

\int \frac{x ^{2}}{16} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int x^{2} d x

Apply the Power Rule

= \frac{1}{16} \cdot \frac{x ^{3}}{3}

Simplify

\frac{1}{16} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{48}

= \frac{x ^{3}}{48}

Add a constant to the solution

= \frac{x ^{3}}{48} + C

\int arcsin (4 x) d x

x \to 2 + lim (\frac{- 3}{x ^{2} - 4})

a re a y = 2 x + 15, y = x^{2}

f (t) = t + 1

x \to 0 lim (\frac{csc ( x )}{x})