What is the tangent of f(x)=x^4-6x^2-x,\at x=1,y=6 ?

The tangent of f(x)=x^4-6x^2-x,\at x=1,y=6 is y=-9x+3

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tangent of f(x)=x^4-6x^2-x,\at x=1,y=6

tangent of

f (x) = x^{4} - 6 x^{2} - x, at x = 1, y = 6

y = - 9 x + 3

Solution steps

Find the tangent point:

(1, - 6)

Find the slope of

f (x) = x^{4} - 6 x^{2} - x : \frac{df ( x )}{d x} = 4 x^{3} - 12 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9

Find the line with slope m=

- 9

and passing through

(1, - 6) : y = - 9 x + 3

y = - 9 x + 3

\int_{0}^{1} x^{2} (2 (1 - x)) d x

\int \frac{2}{1 - e ^{x}} d x

n = 1 \sum \infty \frac{2 n}{9 n - 1}

\frac{\partial}{\partial x} (x y (x - y)^{- 1})

x \to 99 lim (5)

What is the tangent of f(x)=x^4-6x^2-x,\at x=1,y=6 ?
The tangent of f(x)=x^4-6x^2-x,\at x=1,y=6 is y=-9x+3