What is the derivative of sqrt(n) ?

The derivative of sqrt(n) is 1/(2sqrt(n))

What is the first derivative of sqrt(n) ?

The first derivative of sqrt(n) is 1/(2sqrt(n))

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derivative of

n

\frac{1}{2 n}

Solution steps

\frac{d}{d n} (n)

Apply radical rule:

a = a^{\frac{1}{2}}

= \frac{d}{d n} (n^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} n^{\frac{1}{2} - 1}

Simplify

\frac{1}{2} n^{\frac{1}{2} - 1} : \frac{1}{2 n}

= \frac{1}{2 n}

\int y^{2} d y

\int_{1}^{2} \frac{3}{t ^{4}} d t

x^{2} y^{^{'}} + 2 x^{3} y = y^{2} (1 + 2 x^{2})

\frac{d}{d x} (9 x + 2)

\int \frac{x + 2 x - 1}{2 x x - 1} d x

What is the derivative of sqrt(n) ?
The derivative of sqrt(n) is 1/(2sqrt(n))
What is the first derivative of sqrt(n) ?
The first derivative of sqrt(n) is 1/(2sqrt(n))