What is the tangent of f(x)=x^4-20x^2+64,\at x=-2 ?

The tangent of f(x)=x^4-20x^2+64,\at x=-2 is y=48x+96

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=x^4-20x^2+64,\at x=-2

tangent of

f (x) = x^{4} - 20 x^{2} + 64, at x = - 2

y = 48 x + 96

Solution steps

Find the tangent point:

(- 2, 0)

Find the slope of

f (x) = x^{4} - 20 x^{2} + 64 : \frac{df ( x )}{d x} = 4 x^{3} - 40 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 48

Find the line with slope m=

48

and passing through

(- 2, 0) : y = 48 x + 96

y = 48 x + 96

f a c t or 24 x^{3} + 24 x^{2}

\frac{d}{d x} (2 x^{2} - \frac{1}{x ^{2}} + \frac{1}{x ^{3}})

\int \frac{31}{x ^{3} - 27} d x

\frac{\partial}{\partial y} (6 x^{\frac{y}{z}})

\int \frac{2}{\frac{1}{2} + x ^{2}} d x

What is the tangent of f(x)=x^4-20x^2+64,\at x=-2 ?
The tangent of f(x)=x^4-20x^2+64,\at x=-2 is y=48x+96