What is the tangent of f(x)=2xcos(x),\at x=(3pi)/2 ?

The tangent of f(x)=2xcos(x),\at x=(3pi)/2 is y=3pix-(9pi^2)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=2xcos(x),\at x=(3pi)/2

tangent of

f (x) = 2 x cos (x), at x = \frac{3 π}{2}

y = 3 π x - \frac{9 π ^{2}}{2}

Solution steps

Find the tangent point:

(\frac{3 π}{2}, 0)

Find the slope of

f (x) = 2 x cos (x) : \frac{df ( x )}{d x} = 2 (cos (x) - x sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3 π

Find the line with slope m=

3 π

and passing through

(\frac{3 π}{2}, 0) : y = 3 π x - \frac{9 π ^{2}}{2}

y = 3 π x - \frac{9 π ^{2}}{2}

\int 2 sin^{3} (x co) s^{5} x d x

\frac{d}{d x} ((a x^{2} + b x + c) \cdot e^{- \frac{x}{4}})

x \to - \infty lim (1 + \frac{1}{x})

t an g e n t 3 x, at x = 16

\int x \cdot sin (2 \cdot x) d x

What is the tangent of f(x)=2xcos(x),\at x=(3pi)/2 ?
The tangent of f(x)=2xcos(x),\at x=(3pi)/2 is y=3pix-(9pi^2)/2