What is the derivative of 1/(2sqrt(x))+1/(7x^{6/7)} ?

The derivative of 1/(2sqrt(x))+1/(7x^{6/7)} is -1/(4x^{3/2)}-6/(49x^{13/7)}

What is the first derivative of 1/(2sqrt(x))+1/(7x^{6/7)} ?

The first derivative of 1/(2sqrt(x))+1/(7x^{6/7)} is -1/(4x^{3/2)}-6/(49x^{13/7)}

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derivative of

\frac{1}{2 x} + \frac{1}{7 x ^{\frac{6}{7}}}

- \frac{1}{4 x ^{\frac{3}{2}}} - \frac{6}{49 x ^{\frac{13}{7}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x} + \frac{1}{7 x ^{\frac{6}{7}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) + \frac{d}{d x} (\frac{1}{7 x ^{\frac{6}{7}}})

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{4 x ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{1}{7 x ^{\frac{6}{7}}}) = - \frac{6}{49 x ^{\frac{13}{7}}}

= - \frac{1}{4 x ^{\frac{3}{2}}} - \frac{6}{49 x ^{\frac{13}{7}}}

\int 2 (x - 2) \cdot ln (x - 2) d x

\int \frac{1}{4 - 6 x} d x

d x + d y + x d y = y d x

f (x) = \frac{2 π - x cos ( x )}{x - 2 π}

x \to + 1 lim (\frac{x - 1}{x ^{2} - x})

What is the derivative of 1/(2sqrt(x))+1/(7x^{6/7)} ?
The derivative of 1/(2sqrt(x))+1/(7x^{6/7)} is -1/(4x^{3/2)}-6/(49x^{13/7)}
What is the first derivative of 1/(2sqrt(x))+1/(7x^{6/7)} ?
The first derivative of 1/(2sqrt(x))+1/(7x^{6/7)} is -1/(4x^{3/2)}-6/(49x^{13/7)}