What is the solution for (dy)/(dx)+6(tan(6x))y=9cos(6x) ?

The solution for (dy)/(dx)+6(tan(6x))y=9cos(6x) is y=(9x)/(sec(6x))+(c_{1})/(sec(6x))

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(dy)/(dx)+6(tan(6x))y=9cos(6x)

\frac{d y}{d x} + 6 (tan (6 x)) y = 9 cos (6 x)

y = \frac{9 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

Solution steps

\frac{d y}{d x} + 6 (tan (6 x)) y = 9 cos (6 x)

Solve linear ODE:

y = \frac{9 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

y = \frac{9 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

\frac{d}{d x} (8 x^{2} - x^{3})

\frac{d ^{2} y}{d x ^{2}} = \frac{1}{x} + 2

x \to - 2 lim (\frac{∣ x - 2 ∣}{x - 2})

\frac{\partial}{\partial x} ((x^{3} + y^{3})^{10})

\int \frac{5 - x ^{2}}{3 x ^{3} + x} d x

What is the solution for (dy)/(dx)+6(tan(6x))y=9cos(6x) ?
The solution for (dy)/(dx)+6(tan(6x))y=9cos(6x) is y=(9x)/(sec(6x))+(c_{1})/(sec(6x))