What is laplacetransform-4cos(3t) ?

The answer to laplacetransform-4cos(3t) is -(4s)/(s^2+9)

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laplacetransform-4cos(3t)

laplace transform

- 4 cos (3 t)

- \frac{4 s}{s ^{2} + 9}

Solution steps

L {- 4 cos (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 4 L {cos (3 t)}

L {cos (3 t)} : \frac{s}{s ^{2} + 9}

= - 4 \cdot \frac{s}{s ^{2} + 9}

Refine

- 4 \frac{s}{s ^{2} + 9} : - \frac{4 s}{s ^{2} + 9}

= - \frac{4 s}{s ^{2} + 9}

\int \frac{10800 q}{9 q ^{2} + 675} d q

\int \frac{( arctan ( x ) )}{1 + x ^{2}} d x

f (x) = x^{3}, (0, 0)

f (x) = 3 (5 - x)^{2}

\frac{d}{d x} ((9 x + 2)^{\frac{2}{3}})

What is laplacetransform-4cos(3t) ?
The answer to laplacetransform-4cos(3t) is -(4s)/(s^2+9)