What is the integral of e^x(3e^x-2)^2 ?

The integral of e^x(3e^x-2)^2 is 1/9 (3e^x-2)^3+C

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integral of e^x(3e^x-2)^2

\int e^{x} (3 e^{x} - 2)^{2} d x

\frac{1}{9} (3 e^{x} - 2)^{3} + C

Solution steps

\int e^{x} (3 e^{x} - 2)^{2} d x

Apply u-substitution

: \int \frac{u ^{2}}{3} d u

= \int \frac{u ^{2}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{1}{3} \cdot \frac{u ^{3}}{3}

Substitute back

u = 3 e^{x} - 2

= \frac{1}{3} \cdot \frac{( 3 e ^{x} - 2 ) ^{3}}{3}

Simplify

\frac{1}{3} \cdot \frac{( 3 e ^{x} - 2 ) ^{3}}{3} : \frac{1}{9} (3 e^{x} - 2)^{3}

= \frac{1}{9} (3 e^{x} - 2)^{3}

Add a constant to the solution

= \frac{1}{9} (3 e^{x} - 2)^{3} + C

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What is the integral of e^x(3e^x-2)^2 ?
The integral of e^x(3e^x-2)^2 is 1/9 (3e^x-2)^3+C