(\partial)/(\partial x)(x^2+2y^2-1)

解答

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} - 1)

2 x

求解步骤

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} - 1)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (2 y^{2}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

\frac{\partial}{\partial x} (1) = 0

= 2 x + 0 - 0

化简

= 2 x

\int \frac{x ^{2}}{2 - x ^{2}} d x

\frac{\partial}{\partial y} (x e^{3 y})

\frac{\partial}{\partial x} (\frac{4 x - 3 y}{4 x + 3 y})

d er i v a t i v e f (x) = - 16 t^{2} - 8 t + 64

t an g e n t (x^{2} - 3) (x^{3} - 2 x)