What is laplacetransform-t^2\delta(t-2) ?

The answer to laplacetransform-t^2\delta(t-2) is -4e^{-2s}

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laplacetransform-t^2\delta(t-2)

laplace transform

- t^{2} δ (t - 2)

- 4 e^{- 2 s}

Solution steps

L {- t^{2} δ (t - 2)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - L {t^{2} δ (t - 2)}

L {t^{2} δ (t - 2)} : 4 e^{- 2 s}

= - 4 e^{- 2 s}

\int x^{5} x^{3} + 1 d x

\int (4 x^{2} + 3 x) cos (x) d x

\frac{d}{d x} (x e^{3 x^{2} + 1})

\int (y^{2} - \frac{1}{y ^{2}})^{3} d y

\int cos (a t) d t

What is laplacetransform-t^2\delta(t-2) ?
The answer to laplacetransform-t^2\delta(t-2) is -4e^{-2s}