What is the f(x)=sqrt(2x^2-x+9) ?

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f(x)=sqrt(2x^2-x+9)

f (x) = 2 x^{2} - x + 9

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{71}{2 2}

Y Intercepts : (0, 3)

Asymptotes : None

Extreme Points : Minimum (\frac{1}{4}, \frac{71}{2 2})

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{71}{2 2}, \infty)

Solution steps

Domain of

2 x^{2} - x + 9 : - \infty < x < \infty

Range of

2 x^{2} - x + 9 : f (x) \geq \frac{71}{2 2}

Axis interception points of

2 x^{2} - x + 9 :

Y Intercepts

: (0, 3)

Asymptotes of

2 x^{2} - x + 9 :

None

Extreme Points of

2 x^{2} - x + 9 :

Minimum

(\frac{1}{4}, \frac{71}{2 2})

f (x) = 2 - \frac{2}{3} x

\frac{d}{d x} (ln (ln (sec (2 x))))

y = 3 x + \frac{4}{x}

\frac{d u + 2 d v}{u + 2 v} = 0

x \to 2 lim (3 x^{2} - 2 x + 1)