What is the limit as x approaches 0 of k/(x(x+1)) ?

The limit as x approaches 0 of k/(x(x+1)) is diverges

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limit as x approaches 0 of k/(x(x+1))

x \to 0 lim (\frac{k}{x ( x + 1 )})

diverges

Solution steps

x \to 0 lim (\frac{k}{x ( x + 1 )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{k}{x ( x + 1 )}) = \infty

x \to 0 - lim (\frac{k}{x ( x + 1 )}) = - \infty

= diverges

x \to 3 + lim (\frac{x + 1}{3 - x})

d er i v a t i v e y = 2 x

\frac{d}{d x} (\frac{2}{5} x^{3} cos (x))

\frac{d}{d x} (ln (x^{2} y))

\frac{d}{d x} (\frac{6 x ^{2} + 8 x + 8}{x})

What is the limit as x approaches 0 of k/(x(x+1)) ?
The limit as x approaches 0 of k/(x(x+1)) is diverges