What is (\partial)/(\partial x)(18x^2y+12xy^2) ?

The answer to (\partial)/(\partial x)(18x^2y+12xy^2) is 36yx+12y^2

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(\partial)/(\partial x)(18x^2y+12xy^2)

\frac{\partial}{\partial x} (18 x^{2} y + 12 x y^{2})

36 y x + 12 y^{2}

Solution steps

\frac{\partial}{\partial x} (18 x^{2} y + 12 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (18 x^{2} y) + \frac{\partial}{\partial x} (12 x y^{2})

\frac{\partial}{\partial x} (18 x^{2} y) = 36 y x

\frac{\partial}{\partial x} (12 x y^{2}) = 12 y^{2}

= 36 y x + 12 y^{2}

arcsin (\frac{x ^{2} - 1}{x})

x \to 3 lim (3 x + 9)

\frac{d}{d x} (2 x e^{y})

\int - 4 d x

\frac{\partial}{\partial y} (3 x - 4 y)

What is (\partial)/(\partial x)(18x^2y+12xy^2) ?
The answer to (\partial)/(\partial x)(18x^2y+12xy^2) is 36yx+12y^2