What is the derivative of 2sin(3pix) ?

The derivative of 2sin(3pix) is 6picos(3pix)

What is the first derivative of 2sin(3pix) ?

The first derivative of 2sin(3pix) is 6picos(3pix)

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derivative of

2 sin (3 π x)

6 π cos (3 π x)

Solution steps

\frac{d}{d x} (2 sin (3 π x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (3 π x))

Apply the chain rule:

cos (3 π x) \frac{d}{d x} (3 π x)

= cos (3 π x) \frac{d}{d x} (3 π x)

\frac{d}{d x} (3 π x) = 3 π

= 2 cos (3 π x) \cdot 3 π

Simplify

= 6 π cos (3 π x)

y^{^{'}} + \frac{2}{x} y = x, y (1) = 0

t an g e n t y = e^{x}

p a r i t y x \cdot tan (x)

l a pl a ce t r an s f or m t \cdot cos (t)

\frac{d}{d x} (sinh^{3} (\frac{1}{x}))

What is the derivative of 2sin(3pix) ?
The derivative of 2sin(3pix) is 6picos(3pix)
What is the first derivative of 2sin(3pix) ?
The first derivative of 2sin(3pix) is 6picos(3pix)