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Popular Calculus >

area y=-1/2 x^2+2,y=0

Solution

area

y = - \frac{1}{2} x^{2} + 2, y = 0

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} - \frac{1}{2} x^{2} + 2 d x

Solve

\int_{- 2}^{2} - \frac{1}{2} x^{2} + 2 d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is area y=-1/2 x^2+2,y=0 ?
The answer to area y=-1/2 x^2+2,y=0 is 16/3