What is the integral of (3x(8-x))/(135) ?

The integral of (3x(8-x))/(135) is 1/45 (4x^2-(x^3)/3)+C

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integral of (3x(8-x))/(135)

\int \frac{3 x ( 8 - x )}{135} d x

\frac{1}{45} (4 x^{2} - \frac{x ^{3}}{3}) + C

Solution steps

\int \frac{3 x ( 8 - x )}{135} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{135} \cdot \int x (8 - x) d x

Cancel the common factor:

3

= \frac{1}{45} \cdot \int x (8 - x) d x

Expand

x (8 - x) : 8 x - x^{2}

= \frac{1}{45} \cdot \int 8 x - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{45} (\int 8 x d x - \int x^{2} d x)

\int 8 x d x = 4 x^{2}

\int x^{2} d x = \frac{x ^{3}}{3}

= \frac{1}{45} (4 x^{2} - \frac{x ^{3}}{3})

Add a constant to the solution

= \frac{1}{45} (4 x^{2} - \frac{x ^{3}}{3}) + C

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What is the integral of (3x(8-x))/(135) ?
The integral of (3x(8-x))/(135) is 1/45 (4x^2-(x^3)/3)+C