What is the limit as x approaches-1-of sqrt(-4x-4)-8 ?

The limit as x approaches-1-of sqrt(-4x-4)-8 is -8

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limit as x approaches-1-of sqrt(-4x-4)-8

x \to - 1 - lim (- 4 x - 4 - 8)

- 8

Solution steps

x \to - 1 - lim (- 4 x - 4 - 8)

Plug in the value

x = - 1

= - 4 (- 1) - 4 - 8

Simplify

- 4 (- 1) - 4 - 8 : - 8

= - 8

y^{^{'}} + y = \frac{1 - x}{2 x ^{2}}

y^{6} + x^{3} = y^{2} + 12 x, (0, 1)

x \to - 1 lim (\frac{x}{0})

f (x) = 5 \cdot 3^{x}, at x = 2

\frac{d}{d x} (x^{x} + 1)

What is the limit as x approaches-1-of sqrt(-4x-4)-8 ?
The limit as x approaches-1-of sqrt(-4x-4)-8 is -8