What is the integral from 0 to 3 of (-6)/(xsqrt(x)) ?

The integral from 0 to 3 of (-6)/(xsqrt(x)) is diverges

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integral from 0 to 3 of (-6)/(xsqrt(x))

\int_{0}^{3} \frac{- 6}{x x} d x

diverges

Solution steps

\int_{0}^{3} \frac{- 6}{x x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{0}^{3} \frac{1}{x x} d x

Simplify

x x : x^{\frac{3}{2}}

= - 6 \cdot \int_{0}^{3} \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: [- \frac{2}{x}]_{0}^{3}

= - 6 [- \frac{2}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

(1 - 5 y + x) y^{^{'}} + y = 5 x - 1

(\frac{1}{x})^{^{'}}

\int 9 x cos (x) d x

\frac{d y}{d x} = \frac{1}{y}

f (x) = x^{3} (x - 8)^{2}

What is the integral from 0 to 3 of (-6)/(xsqrt(x)) ?
The integral from 0 to 3 of (-6)/(xsqrt(x)) is diverges