(\partial)/(\partial c)((a^3b^4)/(c^2d^4))

Lösung

\frac{\partial}{\partial c} (\frac{a ^{3} b ^{4}}{c ^{2} d ^{4}})

- \frac{2 a ^{3} b ^{4}}{c ^{3} d ^{4}}

Schritte zur Lösung

\frac{\partial}{\partial c} (\frac{a ^{3} b ^{4}}{c ^{2} d ^{4}})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{a ^{3} b ^{4}}{d ^{4}} \frac{\partial}{\partial c} (\frac{1}{c ^{2}})

Wende Exponentenregel an:

\frac{1}{a} = a^{- 1}

= \frac{a ^{3} b ^{4}}{d ^{4}} \frac{\partial}{\partial c} (c^{- 2})

Wende die Potenzregel an:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{a ^{3} b ^{4}}{d ^{4}} (- 2 c^{- 2 - 1})

Vereinfache

\frac{a ^{3} b ^{4}}{d ^{4}} (- 2 c^{- 2 - 1}) : - \frac{2 a ^{3} b ^{4}}{c ^{3} d ^{4}}

= - \frac{2 a ^{3} b ^{4}}{c ^{3} d ^{4}}

f (x) = arccos (x)

\frac{d}{d x} (3 x e^{- 3 x})

\frac{\partial}{\partial x} (2 cos (4 x))

t a y l or e^{e^{t}}

\int 5 sec^{2} (5 x) tan^{5} (5 x) d x