What is the tangent of f(x)=-1/x ?

The tangent of f(x)=-1/x is y= 1/(a_{0)^2}x-2/(a_{0)}

tangent of f(x)=-1/x

tangent of

f (x) = - \frac{1}{x}

y = \frac{1}{a _{0}^{2}} x - \frac{2}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - \frac{1}{a _{0}})

Find the slope of

f (x) = - \frac{1}{x} : \frac{df ( x )}{d x} = \frac{1}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{a _{0}^{2}}

Find the line with slope m=

\frac{1}{a _{0}^{2}}

and passing through

(a_{0}, - \frac{1}{a _{0}}) : y = \frac{1}{a _{0}^{2}} x - \frac{2}{a _{0}}

y = \frac{1}{a _{0}^{2}} x - \frac{2}{a _{0}}

d er i v a t i v e f (x) = 1 + x

\int \frac{\frac{π}{6}}{0} sin (x) cos^{3} (x) d x

in v erse l a pl a ce \frac{1}{s ^{2}}

\int - \frac{2000}{x ^{2}} d x

x \to \infty lim (- \frac{1}{2 x})

What is the tangent of f(x)=-1/x ?
The tangent of f(x)=-1/x is y= 1/(a_{0)^2}x-2/(a_{0)}