(\partial)/(\partial x)(2x-sqrt(3y^2+z^2))

解

\frac{\partial}{\partial x} (2 x - 3 y^{2} + z^{2})

2

解答ステップ

\frac{\partial}{\partial x} (2 x - 3 y^{2} + z^{2})

y, z

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (3 y^{2} + z^{2})

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (3 y^{2} + z^{2}) = 0

= 2 - 0

簡素化

= 2