斜率 y=(-4x^2+12)/(2x+2)

解答

斜率

y = \frac{- 4 x ^{2} + 12}{2 x + 2}

- \frac{2 ( x ^{2} + 2 x + 3 )}{( x + 1 ) ^{2}}

求解步骤

y = \frac{- 4 x ^{2} + 12}{2 x + 2}

要确定函数的斜率，对

\frac{- 4 x ^{2} + 12}{2 x + 2}

求导

\frac{d}{d x} (\frac{- 4 x ^{2} + 12}{2 x + 2}) = - \frac{2 ( x ^{2} + 2 x + 3 )}{( x + 1 ) ^{2}}

- \frac{2 ( x ^{2} + 2 x + 3 )}{( x + 1 ) ^{2}}