What is the derivative of 9sqrt(x)+7 ?

The derivative of 9sqrt(x)+7 is 9/(2sqrt(x))

What is the first derivative of 9sqrt(x)+7 ?

The first derivative of 9sqrt(x)+7 is 9/(2sqrt(x))

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\frac{d}{d x} (9 x + 7)

\frac{9}{2 x}

Solution steps

\frac{d}{d x} (9 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x) + \frac{d}{d x} (7)

\frac{d}{d x} (9 x) = \frac{9}{2 x}

\frac{d}{d x} (7) = 0

= \frac{9}{2 x} + 0

Simplify

= \frac{9}{2 x}

6 y^{^{''}} - 6 y^{^{'}} + 39 y = 0

x \to 0 lim ((1 + \frac{x}{2})^{\frac{3}{x}})

\frac{d}{d x} (ln (x^{2} - 4 x + 5))

x_{1} + x_{2} + x_{3} - 12

\int e^{- x} cos (8 x) d x

What is the derivative of 9sqrt(x)+7 ?
The derivative of 9sqrt(x)+7 is 9/(2sqrt(x))
What is the first derivative of 9sqrt(x)+7 ?
The first derivative of 9sqrt(x)+7 is 9/(2sqrt(x))