What is the derivative of 9/(x^4) ?

The derivative of 9/(x^4) is -(36)/(x^5)

What is the first derivative of 9/(x^4) ?

The first derivative of 9/(x^4) is -(36)/(x^5)

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\frac{d}{d x} (\frac{9}{x ^{4}})

- \frac{36}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 4 x^{- 4 - 1})

Simplify

9 (- 4 x^{- 4 - 1}) : - \frac{36}{x ^{5}}

= - \frac{36}{x ^{5}}

a re a 3 x^{2}, - 3 x + 6, - 4, 2

x \to 0 + lim (\frac{x + 92}{x})

\int \frac{e ^{x}}{1 + e ^{x}} d x

\int x^{9} x^{5} + 3 d x

\frac{d}{d x} (ln ((5 x)^{2}))

What is the derivative of 9/(x^4) ?
The derivative of 9/(x^4) is -(36)/(x^5)
What is the first derivative of 9/(x^4) ?
The first derivative of 9/(x^4) is -(36)/(x^5)