What is the integral of (x-1)/(x^2+2x) ?

The integral of (x-1)/(x^2+2x) is -1/2 ln|x|+3/2 ln|x+2|+C

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integral of (x-1)/(x^2+2x)

\int \frac{x - 1}{x ^{2} + 2 x} d x

- \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x + 2 ∣ + C

Solution steps

\int \frac{x - 1}{x ^{2} + 2 x} d x

Take the partial fraction of

\frac{x - 1}{x ^{2} + 2 x} : - \frac{1}{2 x} + \frac{3}{2 ( x + 2 )}

= \int - \frac{1}{2 x} + \frac{3}{2 ( x + 2 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{2 x} d x + \int \frac{3}{2 ( x + 2 )} d x

\int \frac{1}{2 x} d x = \frac{1}{2} ln ∣ x ∣

\int \frac{3}{2 ( x + 2 )} d x = \frac{3}{2} ln ∣ x + 2 ∣

= - \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x + 2 ∣

Add a constant to the solution

= - \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x + 2 ∣ + C

What is the integral of (x-1)/(x^2+2x) ?
The integral of (x-1)/(x^2+2x) is -1/2 ln|x|+3/2 ln|x+2|+C