What is the derivative of 2(3-x^2^5) ?

The derivative of 2(3-x^2^5) is -20x(3-x^2)^4

What is the first derivative of 2(3-x^2^5) ?

The first derivative of 2(3-x^2^5) is -20x(3-x^2)^4

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\frac{d}{d x} (2 (3 - x^{2})^{5})

- 20 x (3 - x^{2})^{4}

Solution steps

\frac{d}{d x} (2 (3 - x^{2})^{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((3 - x^{2})^{5})

Apply the chain rule:

5 (3 - x^{2})^{4} \frac{d}{d x} (3 - x^{2})

= 5 (3 - x^{2})^{4} \frac{d}{d x} (3 - x^{2})

\frac{d}{d x} (3 - x^{2}) = - 2 x

= 2 \cdot 5 (3 - x^{2})^{4} (- 2 x)

Simplify

= - 20 x (3 - x^{2})^{4}

What is the derivative of 2(3-x^2^5) ?
The derivative of 2(3-x^2^5) is -20x(3-x^2)^4
What is the first derivative of 2(3-x^2^5) ?
The first derivative of 2(3-x^2^5) is -20x(3-x^2)^4